Let {\psi }_{nlm} denote the eigenstates of a hydrogen atom in the usual notation. The state \frac{1}{5}\left[ 2{\psi }_{200}- 3{\psi }_{211}+\sqrt{7}{\psi }_{210}- \sqrt{5}{\psi }_{21- 1} \right] is an eigenstate of

Orbital angular Momentum and Hydrogen atom — CSIR Net PYQ (Question 1)

A Orbital angular Momentum and Hydrogen atom previous-year question (PYQ) from Quantum Mechanics (CSIR Net). Read the question, check the correct answer, then practise the full topic.

Question 1 of 24 · 3.5 marks

Let

ψ_{n l m}

denote the eigenstates of a hydrogen atom in the usual notation. The state

\frac{1}{5} [2 ψ_{200} - 3 ψ_{211} + 7 ψ_{210} - 5 ψ_{21 - 1}]

is an eigenstate of

1 $L^{2}$ , but not of the Hamiltonian or $L_{z}$
2the Hamiltonian, but not of $L^{2}$ or $L_{z}$
3the Hamiltonian, $L^{2}$ and $L_{z}$
4 $L^{2}$ and $L_{z}$ , but not of the Hamiltonian

Correct answer: Option 2

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